Compute the TooOld window in integer arithmetic (#99) #102
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@@ -96,7 +96,6 @@ int64_t getSearchPathLength(struct Node *);
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// ==================== BEGIN IMPLEMENTATION ====================
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constexpr int64_t kNominalVersionWindow = 2e9;
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constexpr int64_t kMaxCorrectVersionWindow =
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std::numeric_limits<int32_t>::max();
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static_assert(kNominalVersionWindow <= kMaxCorrectVersionWindow);
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+10
-1
@@ -27,6 +27,15 @@ using namespace weaselab;
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#define SHOW_MEMORY 0
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#endif
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// The window of versions, ending at `newestVersion`, that a subsequent `check`
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// is guaranteed to answer correctly. Reads older than
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// `newestVersion - kNominalVersionWindow` are reported as `TooOld`.
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//
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// This must be an integer constant: `newestVersion - 2e9` is computed in
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// `double`, whose 53 bit mantissa makes the boundary off by up to 512 versions
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// once `newestVersion >= 2^53`.
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constexpr int64_t kNominalVersionWindow = 2000000000;
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// std::span is not trivially constructible. We want a span that leaves its
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// members uninitialized for performance reasons.
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struct TrivialSpan {
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@@ -513,7 +522,7 @@ struct ReferenceImpl {
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int count) const {
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for (int i = 0; i < count; ++i) {
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if (reads[i].readVersion < oldestVersion ||
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reads[i].readVersion < newestVersion - 2e9) {
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reads[i].readVersion < newestVersion - kNominalVersionWindow) {
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results[i] = ConflictSet::TooOld;
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continue;
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}
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+1
-1
@@ -741,7 +741,7 @@ struct __attribute__((visibility("hidden"))) ConflictSet::Impl {
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int iters = skipList.detectConflicts(ranges, count, results);
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for (int i = 0; i < count; ++i) {
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if (reads[i].readVersion < oldestVersion ||
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reads[i].readVersion < newestVersion - 2e9) {
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reads[i].readVersion < newestVersion - kNominalVersionWindow) {
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results[i] = TooOld;
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}
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tls.commits_accum += results[i] == Commit;
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@@ -209,6 +209,22 @@ def test_two_billion_versions():
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cs.check(read(1, b"\x00", b"\xff"))
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def test_too_old_window_precision():
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# Regression test for issue #99: the TooOld window boundary
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# (`newestVersion - 2e9`) must be computed with integer arithmetic. It used
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# to be computed in `double`, whose 53 bit mantissa makes the boundary off
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# by up to ~512 versions once newestVersion >= 2^53.
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for newest in (1 << 53, (1 << 53) + 1, (1 << 53) + 7, 2**63 - 1):
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with DebugConflictSet() as cs:
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cs.addWrites(newest) # No writes; advances newestVersion
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boundary = newest - 2 * 10**9
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# One below the window is TooOld, even though `double` rounding
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# used to put it inside the window.
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assert cs.check(read(boundary - 1, b"k")) == [Result.TOO_OLD]
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# Exactly at the boundary is not TooOld.
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assert cs.check(read(boundary, b"k")) == [Result.COMMIT]
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def test_positive_bytes():
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with DebugConflictSet() as cs:
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cs.addWrites(1, write(b"hello"))
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